LeetCode-693. Binary Number with Alternating Bits [C++][Java]

LeetCode-693. Binary Number with Alternating Bits https://leetcode.com/problems/binary-number-with-alternating-bits/

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values.

Example 1:

Input: n = 5
Output: true
Explanation: The binary representation of 5 is: 101

Example 2:

Input: n = 7
Output: false
Explanation: The binary representation of 7 is: 111.

Example 3:

Input: n = 11
Output: false
Explanation: The binary representation of 11 is: 1011.

Constraints:

1 <= n <= 2^31 - 1

class Solution {
public:
    bool hasAlternatingBits(int n) {
        int prev = n % 2;
        n /= 2;
        while (n > 0) {
            int curr = n % 2;
            if (prev == curr) {return false;}
            prev = curr;
            n /= 2;
        }
        return true;
    }
};

class Solution {
    public boolean hasAlternatingBits(int n) {
        int prev = n % 2;
        n /= 2;
        while (n > 0) {
            int curr = n % 2;
            if (prev == curr) {return false;}
            prev = curr;
            n /= 2;
        }
        return true;
    }
}