C语言作业

#include 
#include 
int main() 
{
	//int key = 0;
	//scanf_s("%d", &key);
	//printf("-----n");
	//char info;
	//scanf_s("%c", &info,1);
	//printf("--------n");
	char name[4][20] = { {""} };
	int score[4][3] = { 0 };
	int rowSum[4] = { 0 };
	int colsSum[4] = { 0 };
	printf("请输入四个学生的信息(name,math,english,py):n");
	for (int i = 0; i < 4; i++) 
	{
		//在二维字符数组中，用一个下标表示每一行的首地址
		scanf_s("%s",name[i],20);		//输入姓名  name[i]就是每一行的首地址
		//三个分数
		for (int j = 0; j < 3; j++) 
		{
			//字符和字串用scanf_s需要长度，数字类不需要
			scanf_s("%d", &score[i][j]);
			//求总分
			rowSum[i] += score[i][j];
		}
		//while(getchar()!='n');
	}
	//前3列
	for (int j = 0; j < 3; j++) 
	{
		for (int i = 0; i < 4; i++) 
		{
			colsSum[j] += score[i][j];
		}
	}
	//最后列
	for (int i = 0; i < 3; i++) 
	{
		colsSum[3] += colsSum[i];
	}

	printf("n姓名t数学t英语tpyt总分n");
	for (int i = 0; i < 4; i++) 
	{
		printf("%st", name[i]);
		for (int j = 0; j < 3; j++)
		{
			printf("%dt", score[i][j]);
		}
		printf("%dt", rowSum[i]);
		printf("n");
	}
	//最后一行
	printf("总分t");
	for (int i = 0; i < 4; i++) 
	{
		printf("%dt", colsSum[i]);
	}

	//	int rowSum[4] = { 0 };
	for (int i = 0; i < 4; i++) 
	{
		for (int j = 0; j < 4 - i - 1; j++) 
		{
			if (rowSum[j] > rowSum[j + 1]) 
			{	
				
				//总分-->数字类直接用赋值
				int temp = rowSum[j];
				rowSum[j] = rowSum[j + 1];
				rowSum[j + 1] = temp;
				//姓名-->字符串必须用字符串处理函数
				char str[20];
				//strcpy(str,name[j])
				strcpy_s(str, 20, name[j]);
				strcpy_s(name[j], 20, name[j+1]);
				strcpy_s(name[j+1], 20,str);
				//分数
				//j:0 j+1:1
				for (int k = 0; k < 3; k++)  //列数
				{
					temp = score[j][k];  //00
					score[j][k] = score[j + 1][k]; //10
					score[j + 1][k] = temp;
				}
			}
		}
	}
	printf("n-------------------------------------n");
	printf("n姓名t数学t英语tpyt总分n");
	for (int i = 0; i < 4; i++)
	{
		printf("%st", name[i]);
		for (int j = 0; j < 3; j++)
		{
			printf("%dt", score[i][j]);
		}
		printf("%dt", rowSum[i]);
		printf("n");
	}
	//最后一行
	printf("总分t");
	for (int i = 0; i < 4; i++)
	{
		printf("%dt", colsSum[i]);
	}
	return 0;
}