python面试题最全(python面试题及答案)

朋友面试凉了，被我无情嘲笑，直到他把题给了我。。。

def task1(str_list: list):
    for i in str_list:
        
        print(i.upper())
    # return [i.upper() for i in str_list]
a = ['qIqiqqq@@@1', 'ily']

task1(a)

def task2(fun):
    print(fun.__doc__)

task2(int)

def task3(str_list: list):
    print(str_list[::-1])

task3(['a', 'b', 'c', 'd'])

def task4(num: int):
    tmp = str(num)
    if num % 3 == 0:
        if num % 5 == 0:
            tmp = 'FizzBuzz'
            return {num: tmp}
        tmp = 'Fizz'
        return {num: tmp}
    elif num % 5 == 0:
        tmp = 'Buzz'
        return {num: tmp}
    return {num: tmp}

print(task4(15))

def task5(num: int):
    # 题目应该有点问题，应该是(0: L] 这个区间，不然结果肯定是0了， 就可以理解为是求num的阶乘后面有几个0
    # 思路; 决定结果末尾0的个数其实就是求5出现的次数，祺中像25 = 5 * 5、50 = 5 * 5 *2 这种5出现了多次要多次统计
    result = 0
    i = 5
    while num >= i:
        result += num // i
        i = i * 5
    return result    

print(task5(100))

def task6(num: int):
    tmp = 200 % num
    return 200 - tmp

print(task6(17))

def task8(num: int):
    tmp = bin(num)
    print(tmp)
    result = 0
    for i in str(tmp):
        if i == '1':
            result += 1
    return result


print(task8(100))

def task9(str1: str):
    return str1.swapcase()

print(task9('QiQi'))

def task10(num_list: list):
    num_list.sort()
    if num_list[0] + num_list[1] > num_list[2]:
        return 'yes'
    return 'no'


print(task10([1, 3, 2]))
print(task10([3, 5, 4]))

def task11(num_list: list):
    # 思路; 两数的最小公倍数就是两数的乘积除以他们的最大公约数
    small_num = min(num_list)
    big_num = max(num_list)
    # 原来两数的积
    tmp = small_num * big_num  #  还没写完。。。