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名师互学网 > IT > 前沿技术 > 大数据 > 大数据系统

hive map(hive设置map个数)

hive map(hive设置map个数)

–创建表,并定义map类型

create table employee(id string, perf map)     
ROW FORMAT DELIMITED                                        
FIELDS TERMINATED BY '	'                              
COLLECTION ITEMS TERMINATED BY ','    --map形式key:value,key:value
MAP KEYS TERMINATED BY ':';  --map形式key:value,key:value

Map中的方法:

    size(Map)函数:可得map的长度。返回值类型:int

    map_keys(Map)函数:可得map中所有的key; 返回值类型: array

    map_values(Map)函数:可得map中所有的value; 返回值类型: array

    判断map中是否包含某个key值:array_contains(map_keys(k_v),‘A’)或者k_V[“A”] is not null

    在k-v对中,若value有多个值的情况,如 {‘k1’:‘01,02,03’} ,如果要用 ‘k1’ 中 '02’作为过滤条件,则语句如下:(这里用到split来处理)select * from t where split(t.params['k1'],',')[1] ;

    如果过滤条件为:k2的值必须为’45’开头,则语句如下:
    (这里用到substr方法来处理,这里注明一下,1和2分别表示起始位置和长度)

    select * from t where substr(t.params[‘k2’],1,2) = ‘45’;

案例:
–字符串转map类型
–1.判断key是否在map中存在

select mm.*, array_contains(map_keys(k_v),'A') from (
select t.w,str_to_map(CONCAT_Ws('&',COLLECT_SET(concat(M,":",mc))),"&",":" ) k_V  --1.拼接字串为 key:value&key:value;2.将拼接的字串转成map类型
FROM (
SELECt 1 W,'A' M,"中" mc
UNIOn ALL
SELECT 1 W,'B' M,"国" mc
UNIOn ALL
SELECT 2 W,'C' M,"好" mc
) T  group by t.w
) mm 
;

结果:

–2.判断key是否在map中存在

select mm.* from (
select t.w,str_to_map(CONCAT_Ws('&',COLLECT_SET(concat(M,":",mc))),"&",":") k_V
FROM (
SELECt 1 W,'A' M,"中" mc
UNIOn ALL
SELECT 1 W,'B' M,"国" mc
UNIOn ALL
SELECT 2 W,'C' M,"好" mc
) T  group by t.w 
) mm where k_V["A"] is not null
;

结果:

–3.map的单行转多行

select mm.*, y.n_m,y.n_mc from (
select t.w,str_to_map(CONCAT_Ws('&',COLLECT_SET(concat(M,":",mc))),"&",":") k_V
FROM (
SELECT 1 W,'A' M,"中" mc
UNIOn ALL
SELECT 1 W,'B' M,"国" mc
UNIOn ALL
SELECT 2 W,'C' M,"好" mc
) T  group by t.w
) mm 
lateral view explode(mm.k_V) y as n_m,n_mc
;

结果:

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