Java判断1至99999的位数以及回文数

import java.sql.SQLOutput;
import java.util.Scanner;
public class huiwenshu {
    public static void main(String[] args) {
        int number = 0, d1, d2, d3, d4, d5;
        Scanner reader = new Scanner(System.in);
        System.out.println("请输入一个1至99999的数");
        number = reader.nextInt();
        if (number < 99999) {
            d5 = number / 10000;
            d4 = number % 10000 / 1000;
            d3 = number % 1000 / 100;
            d2 = number % 100 / 10;
            d1 = number % 10 / 1;
            if (d5 != 0) {
                System.out.println(number + "是五位数");
                if (d5 == d1 && d4 == d3)
                    System.out.println(number + "是回文数");
                else
                    System.out.println(number + "不是回文数");
            }
        else if (d4 != 0){
                System.out.println(number + "是四位数");
            if (d4 == 41 && d3 == d2)
                System.out.println(number + "是回文数");
            else
                System.out.println(number + "不是回文数");
            }
        else    if (d3 != 0){
                System.out.println(number + "是三位数");
            if (d3 == d1)
                System.out.println(number + "是回文数");
            else
                System.out.println(number + "不是回文数");
            }
        else    if (d2 != 0) {
                System.out.println(number + "是两位数");
                if (d2 == d1)
                    System.out.println(number + "是回文数");
                else
                    System.out.println(number + "不是回文数");
            }
        else    if (d1 != 0) {
                System.out.println(number + "是一位数");
                System.out.println(number + "是回文数");
            }
        }
    }
    }