python如何用opencv把一个视频按每10秒一小段切割

import cv2
import os
file_path = 'F:/zmz/ta-chi_data/'

for name in os.listdir(file_path):
    pth = os.path.join(file_path,name)
    nm = name.split('.')[0] # name = "**.mp4"
    print(nm)
    cap = cv2.VideoCapture(pth)
    cap.isOpened()


    if cap.isOpened():  # 当成功打开视频时cap.isOpened()返回True,否则返回False
        # get方法参数按顺序对应下表（从0开始编号)
        rate = cap.get(5)  # 帧速率
        frameNumber = int(cap.get(7))  # 视频文件的帧数
        print(frameNumber)
        duration = frameNumber / rate  # 帧速率/视频总帧数 是时间，除以60之后单位是分钟
        fps = int(rate)  #每一段小视频帧数
        print(duration, fps)
        width = cap.get(cv2.CAP_PROP_frame_WIDTH)
        height = cap.get(cv2.CAP_PROP_frame_HEIGHT)
        i = 0  # 第i帧
        while (True):
            success, frame = cap.read()
            if success:
                i += 1
                # 1s是25帧，fps * 10是250帧即10s的总帧数
                if (i % (fps*10) == 1): # 10s保存一次视频
                # i = 1，251, 501.......
                    if not os.path.exists(f'F:/zmz/sublime/{nm}'):
                        os.makedirs(f'F:/zmz/sublime/{nm}')
                    # videoWriter = cv2.VideoWriter('F:/zmz/sublime/001/' + str(i) + '.avi',cv2.VideoWriter_fourcc('X','V','I','D'), fps,frameSize=(320,240))
                   # videoWriter = cv2.VideoWriter(f'F:/zmz/sublime/{nm}/{nm}_' + str(i // 250 + 1) + '.mp4',cv2.VideoWriter_fourcc('D', 'I', 'V', 'X'), fps,(int(width),int(height)))
                    videoWriter = cv2.VideoWriter(f'F:/zmz/sublime/{nm}/{nm}_' + str(i // 250 + 1) + '.avi', cv2.VideoWriter_fourcc('X','V','I','D'), fps,(int(width), int(height)))
                    videoWriter.write(frame)
                else:
                    videoWriter.write(frame)
            else:
                print('end')
                break

    cap.release()