Python：输入并呈现任意规模矩阵

#用列表呈现矩阵
matrix = []    #定义一个空列表
line = input("Enter the line: ")
row = input("Enter the row: ")
line =int(line)
row = int(row)
number_1 = line * row    #元素总数
number_2 = 1
number_3 = 1
print(f"Enter a {line}*{row} matrix: ")
while number_2 <= number_1:   #输入元素
     if number_2 % row == 1:
          print(f"Enter line {number_3} : ")      #输入提升
          number_3 += 1
     a = input()
     a = int(a)
     matrix.append(a)
     number_2 += 1
print(f"Finished enter matrix. The matrix: ")
number_3 = 0
while number_3 < line * row:
     print(matrix[number_3:number_3 + row])  #用切片呈现行
     number_3 += row

效果不是很好，后续会改进~~~