【Codeup1928 】日期差值

有两个日期，求两个日期之间的天数，如果两个日期是连续的我们规定他们之间的天数为两天。

有多组数据，每组数据有两行，分别表示两个日期，形式为YYYYMMDD。

每组数据输出一行，即日期差值。

20130101
20130105

5

#include
#include

//{平年某月天数，闰年某月天数}
int month[13][2] = {
	{0,0},{31,31},{28,29},{31,31},{30,30},{31,31},{30,30},{31,31},{31,31},{30,30},{31,31},{30,30},{31,31}	
}; 

bool isRunNian(int year){
	bool flag = (year%4==0&&year%100!=0)||(year%400 == 0);
	return flag;
}

int main(int argc, char *argv[])
{
	int time1,year1,month1,day1;
	int time2,year2,month2,day2;
	//允许多组数据	
	//exmple:20210103;20250202
	while((scanf("%d%d",&time1,&time2)) != EOF){
		//始终让time1time2){
			int temp = time1;
			time1 = time2;
			time2 = temp;
		}
		
		year1 = time1/10000,month1 = time1%10000/100,day1 = time1%100;
		year2 = time2/10000,month2 = time2%10000/100,day2 = time2%100;
		int ans = 1;
		//如果 (year1 = year2)&&(month1=month2)&&(day1==day2),判断终止 
		//倒序考虑 
		while((year1 month[month1][isRunNian(year1)]){
				day1 = 1;
				month1++;
			} 
			if(month1 == 13){
				month1=1;
				year1++;
			}
			ans++;	
		}
		printf("%d",ans);
	}
	return 0;
}