Hive Sql完成过滤每组累积去重数低于某值计算

需求概述期望数据基本思路逻辑实现

近期公司开发某项学习功能，改功能有很多学习内容（如java,C,python等方向），每天都会有众多学习用户学习某一项或者多项学习内容。产生数据如下表：

现在想要计算截止每天每个学习内容的截止去重学习用户数，但是截止去重用户数小于等于1的要被过滤，期望数据如下：

截止到2022-01-01，学习内容java的为去重用户数为1，学习内容C的为去重用户数为2，学习内容Python的为去重用户数为1。所以2022-01-01学习内容为java和python的都要内过滤。

将所有天数和学习种类去重后作为临时表b，将明细表作为表a，a表内关联b表，关联条件为a的pdate要小于等于b的pdate并且学习内容一致，这样每个学习种类的截止到每天的学习用户数就取出了。再分组求和，having过滤组内数量即可。

with tmp as ( -- 基础数据
select '2022-01-01' as pdate,'java' as icate, 'u1' as user
union all 
select '2022-01-02' as pdate,'java' as icate, 'u1' as user
union all 
select '2022-01-02' as pdate,'java' as icate, 'u2' as user
union all 
select '2022-01-01' as pdate,'C' as icate, 'u1' as user
union all 
select '2022-01-01' as pdate,'C' as icate, 'u3' as user
union all 
select '2022-01-01' as pdate,'Python' as icate, 'u4' as user
union all 
select '2022-01-02' as pdate,'Python' as icate, 'u4' as user
union all 
select '2022-01-02' as pdate,'Python' as icate, 'u5' as user
union all 
select '2022-01-02' as pdate,'Python' as icate, 'u6' as user
),
tmp1 as (
select distinct pdate,icate from tmp
)
select
    a.pdate,a.icate,count(distinct a.user) as icount
from 
    tmp a 
join 
    tmp1 b
on 
    a.pdate <= b.pdate 
and 
    a.icate = b.icate
group by 
    a.pdate,a.icate
having 
    icount > 1;