python
1.十进制转换为ASCLL值
已知 十进制为：55,56,54,79,115,69,114,116,107,49,50
a = [55,56,54,79,115,69,114,116,107,49,50] c=“” for i in a: b = chr(i) c = c + b print(c) 结果为 786OsErtk12
2.将字符串转换为数组（数）
s = "x35x35x2cx35x36x2cx35x34x2cx37x39x2cx31x31x35x2cx36x39x2cx31x31x34x2cx31x31x36x2cx31x30x37x2cx34x39x2cx35x30" print(s) 结果为 55,56,54,79,115,69,114,116,107,49,50
3.ASCLL编码转换
/119/101/108/99/111/109/101/116/111/97/116/116/97/99/107/97/110/100/100/101/102/101/110/99/101/119/111/114/108/100
import re
r="/119/101/108/99/111/109/101/116/111/97/116/116/97/99/107/97/110/100/100/101/102/101/110/99/101/119/111/114/108/100"
r=re.split("/",r)
flag=""
for i in range(1,len(r)):
flag=flag+chr(int(r[i]))
print (flag)
结果：welcometoattackanddefenceworld
4.二进制转字符串
import re
a='01100110011011000110000101100111011110110100011001110101010011100101111101100111011010010100011001111101'
b=re.findall(r'.{8}',a)
flag=''
for i in b:
flag += chr(int(i,2))
print(flag)
