# 既可以加密又可解密
s = 'jkl'
s2 = 'mno'
d = {}
for c in (65, 97):
for i in range(26):
d[chr(i + c)] = chr((i + 13) % 26 + c)
print(''.join(d.get(c, c) for c in s)) # 编码
print(''.join(d.get(c, c) for c in s2)) # 解码
# 既可以加密又可解密
s = 'jkl'
s2 = 'mno'
d = {}
for c in (65, 97):
for i in range(26):
d[chr(i + c)] = chr((i + 13) % 26 + c)
print(''.join(d.get(c, c) for c in s)) # 编码
print(''.join(d.get(c, c) for c in s2)) # 解码
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