Leetcode.537 复数乘法

char * complexNumberMultiply(char * num1, char * num2){
    int a,b,c,d;
    sscanf(num1,"%d+%di",&a,&b);
    sscanf(num2,"%d+%di",&c,&d);
    char* result=(char*)malloc(15*sizeof(char));
    sprintf(result,"%d+%di",a*c-b*d,a*d+b*c);
    return result;
}

1.sscanf的用法

 2.sprintf的用法

参考:http://t.csdn.cn/vFllH