C++ | 用C语言实现多态和一些思考

const float pi = 3.14;
typedef float (*area)(void*);//函数指针


typedef struct Shape
{
	area p;
}Shape;

typedef struct Circle
{
	Shape shape;
	float radius;
}Circle;

typedef struct Square
{
	Shape shape;
	float length;
}Square;

float square_area(void* cp) {
	if (cp == NULL) return 0;
	printf("square class area n"); 
	Square* sq = (Square*)cp;
	float area = sq->length * sq->length; return area;
}

float circle_area(void* cp) {
	if (cp == NULL) return 0;
	printf("ciecle class area n");
	Circle* sq = (Circle*)cp;
	float area = sq->radius * sq->radius*pi; return area;
}

int main()
{
	Square s;
	s.length = 10;
	Circle c;
	c.radius = 10;
	s.shape.p = square_area;//与自己的计算函数绑定
	c.shape.p = circle_area;//与自己的计算函数绑定
	Shape* shape = NULL;
	shape = (Shape*)&s;//此时将s空间给shape,而shape只能调动它的第一个成员,刚好和Square的第一个成员相同
	cout << "Square area:" << shape->p(&s)<p(&c)< 
当Square中两个成员调换时,编译能通过,但是执行时却发生错误
 
typedef struct Square
{
	float length;
	Shape shape;
	
}Square;
 
 
然后我又把Shape中添加了一个float,目的是为了和用shape类型偏移时能够和Square对应起来,当Square类型空间给shape指针时能够正确的偏移到计算函数,但是如果Square中还是shape类型的话,又会出错,因为shape类型已经让我改了
 
 shape指针以为已经偏移到了它的函数指针p这里,但是这是Square的空间啊!,偏移到了float,所以出错,此时将Square第二个成员改为和shape一致就行了
 
 
 虽然这样有点不符合继承的概念了…