【深基2.例8】再分肥宅水 - 洛谷
C++代码:
#include#include using namespace std; int main() { int n,ans02; double t,ans01; cin>>t>>n; ans01=t/n; ans02=n*2; printf("%.3fn%d",ans01,ans02); return 0; }
python3代码:
""" P5706 【深基2.例8】再分肥宅水(python3实现) https://www.luogu.com.cn/problem/P5706 """ t,n= map( str, input().strip().split() ) ans01=float(t)/int(n) ans02=int(n)*2 print( "%.3f"%ans01 ) print( ans02 )
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