1.题目
https://leetcode-cn.com/problems/add-two-numbers/
2.个人题解
# 第一次完美提交，和官方答案思路一样，记录下
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
class Solution:
def addTwonumbers(self, l1, l2) :
new = ListNode() # 初始化
head = new
temp = 0
sums = 0
while l1 or l2:
if l1 and l2:
sums = l1.val + l2.val + temp
if sums >= 10:
temp = 1
sums = sums - 10
else:
temp = 0
l1 = l1.next
l2 = l2.next
elif l1 or l2:
if temp == 0:
if l1:
new.next = l1
new = l1
l1 = None
break
elif l2:
new.next = l2
new = l2
l2 = None
break
elif temp == 1:
if l1:
sums = l1.val + temp
l1 = l1.next
elif l2:
sums = l2.val + temp
l2 = l2.next
if sums >= 10:
temp = 1
sums = sums - 10
else:
temp = 0
r = ListNode()
r.val = sums
sums = 0
new.next = r
new = r
if not l1 and not l2 and temp:
r = ListNode()
r.val = 1
new.next = r
return head.next
# debug
debug = Solution()
l1 = ListNode(6, ListNode(1, ListNode(2)))
l2 = ListNode(4, ListNode(4))
d = debug.addTwonumbers(l1, l2)
while d:
print(d.val)
d = d.next
3.题目
https://leetcode-cn.com/problems/two-sum/
4.个人题解
# 查找-哈希表法
from typing import List
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
res = []
temp = dict()
for i, num in enumerate(nums):
temp[num] = i
for i, num in enumerate(nums):
if target-num in temp.keys() and i != temp[target-num]:
return [i, temp[target-num]]
