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AQS源码解析(ReentrantLock)

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AQS源码解析(ReentrantLock)

实例化

public ReentrantLock(boolean fair) {
sync = fair ? new FairSync() : new NonfairSync();
}
fair为true是公平锁,false为false是非公平锁。

公平锁的lock()方法
final void lock() {
            acquire(1);
        }
public final void acquire(int arg) {
        if (!tryAcquire(arg) &&
            acquireQueued(addWaiter(Node.EXCLUSIVE), arg))
            selfInterrupt();
    }

tryAcquire 尝试获取独占锁

protected final boolean tryAcquire(int acquires) {
            final Thread current = Thread.currentThread();
            int c = getState();
            if (c == 0) {
                if (!hasQueuedPredecessors() &&
                    compareAndSetState(0, acquires)) {
                    setExclusiveOwnerThread(current);
                    return true;
                }
            }
            else if (current == getExclusiveOwnerThread()) {
                int nextc = c + acquires;
                if (nextc < 0)
                    throw new Error("Maximum lock count exceeded");
                setState(nextc);
                return true;
            }
            return false;
        }

先获取同步对象的状态getState();
如果状态是0,还没有被线程占用。
hasQueuedPredecessors();看看同步队列中是否有等待的线程,如果有,获取锁失败(独占锁肯定失败,共享锁不一定)。
如果没有使用compareAndSetState(0, acquires);使用cas的方式把状态从0改为1;
把获取到资源的线程调用setExclusiveOwnerThread(current);也就是设置当前的独占线程设置为当前的线程;

else if (current == getExclusiveOwnerThread())
如果状态不是0,判断是否还是当前的线程(也就是ExclusiveOwnerThread);如果是让state加1,int nextc = c + acquires;

如果tryAcquire(arg)失败,就会把当前的线程添加到CLH队列中。

private Node addWaiter(Node mode) {
        Node node = new Node(Thread.currentThread(), mode);
        // Try the fast path of enq; backup to full enq on failure
        Node pred = tail;
        if (pred != null) {
            node.prev = pred;
            if (compareAndSetTail(pred, node)) {
                pred.next = node;
                return node;
            }
        }
        enq(node);
        return node;
    }

node.prev = pred;
if (pred != null)如果CLH队列中有节点的话
把当前节点的前置节点指向好。
使用cas把当前节点放到CLH队列的尾部compareAndSetTail(pred, node);

如果CLH队列中没有节点的话调用enq(node)方法;

private Node enq(final Node node) {
        for (;;) {
            Node t = tail;
            if (t == null) { // Must initialize
                if (compareAndSetHead(new Node()))
                    tail = head;
            } else {
                node.prev = t;
                if (compareAndSetTail(t, node)) {
                    t.next = node;
                    return t;
                }
            }
        }
    }

先初始化一个空的Node节点作为head节点compareAndSetHead(new Node());
然后再把新节点添加到空的节点的后面;

final boolean acquireQueued(final Node node, int arg) {
        boolean failed = true;
        try {
            boolean interrupted = false;
            for (;;) {
                final Node p = node.predecessor();
                if (p == head && tryAcquire(arg)) {
                    setHead(node);
                    p.next = null; // help GC
                    failed = false;
                    return interrupted;
                }
                if (shouldParkAfterFailedAcquire(p, node) &&
                    parkAndCheckInterrupt())
                    interrupted = true;
            }
        } finally {
            if (failed)
                cancelAcquire(node);
        }
    }

把刚添加到队列中的Thread节点,准备阻塞,然后等待获取锁。
拿到当前节点的前置节点final Node p = node.predecessor();先判断if (p == head && tryAcquire(arg)) 前置节点是否已经变成head节点,如果变成head节点,这时候再去尝试获取锁。

private static boolean shouldParkAfterFailedAcquire(Node pred, Node node) {
        int ws = pred.waitStatus;
        if (ws == Node.SIGNAL)
            /*
             * This node has already set status asking a release
             * to signal it, so it can safely park.
             */
            return true;
        if (ws > 0) {
            /*
             * Predecessor was cancelled. Skip over predecessors and
             * indicate retry.
             */
            do {
                node.prev = pred = pred.prev;
            } while (pred.waitStatus > 0);
            pred.next = node;
        } else {
            /*
             * waitStatus must be 0 or PROPAGATE.  Indicate that we
             * need a signal, but don't park yet.  Caller will need to
             * retry to make sure it cannot acquire before parking.
             */
            compareAndSetWaitStatus(pred, ws, Node.SIGNAL);
        }
        return false;
    }

if (ws == Node.SIGNAL)如果当前节点的前驱节点是signal,当前节点可以被阻塞;
if (ws > 0) 如果前驱节点大于0,这个前驱节点就会被移除队列,

当前驱节点的waitStatus的状态是0或者PROPAGATE时,使用cas将其设置为SIGNAL,然后当前节点才可以park。

private final boolean parkAndCheckInterrupt() {
        LockSupport.park(this);
        return Thread.interrupted();
    }

阻塞当前节点,并返回当前节点的阻塞状态。

公平锁的unlock方法
protected final boolean tryRelease(int releases) {
            int c = getState() - releases;
            if (Thread.currentThread() != getExclusiveOwnerThread())
                throw new IllegalMonitorStateException();
            boolean free = false;
            if (c == 0) {
                free = true;
                setExclusiveOwnerThread(null);
            }
            setState(c);
            return free;
        }

如果当前线程不等于获取独占锁的线程,那么抛出异常
if (Thread.currentThread() != getExclusiveOwnerThread())
throw new IllegalMonitorStateException();

如果c==0 把获取独占锁的线程设置为null;

private void unparkSuccessor(Node node) {
        /*
         * If status is negative (i.e., possibly needing signal) try
         * to clear in anticipation of signalling.  It is OK if this
         * fails or if status is changed by waiting thread.
         */
        int ws = node.waitStatus;
        if (ws < 0)
            compareAndSetWaitStatus(node, ws, 0);

        /*
         * Thread to unpark is held in successor, which is normally
         * just the next node.  But if cancelled or apparently null,
         * traverse backwards from tail to find the actual
         * non-cancelled successor.
         */
        Node s = node.next;
        if (s == null || s.waitStatus > 0) {
            s = null;
            for (Node t = tail; t != null && t != node; t = t.prev)
                if (t.waitStatus <= 0)
                    s = t;
        }
        if (s != null)
            LockSupport.unpark(s.thread);
    }

如果后一个节点是null或者waitStatus大于0,那么就从尾部开始遍历,找到正常阻塞的一个节点。

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