python实现矩阵乘法

# 2 3 3 4
# 1 2 3
# 4 5 6
# 1 2 3 4
# 5 6 7 8
# 9 10 11 12
lst1, lst2 = [], []
n1,m1,n2,m2 = map(int,input().split())
for i in range(n1):
    nums = list(map(int,input().split())) #输入一行数据
    lst1.append(nums)
for i in range(n2):
    nums = list(map(int,input().split()))
    lst2.append(nums)
res = []
for i in range(n1):
    res.append([])
    for j in range(m2):
        lst4 = []
        lst3 = lst1[i]
        for k in range(n2):
            lst4.append(lst2[k][j])
        res_num = sum(map(lambda x,y:x*y,lst3,lst4))
        res[i].append(res_num)
print(res)

import numpy as np
print('numpy:',np.dot(lst1,lst2)) #使用numpy验证结果

2 3 3 4
1 2 3
4 5 6
1 2 3 4
5 6 7 8
9 10 11 12
[[38, 44, 50, 56], [83, 98, 113, 128]]
numpy: [[ 38  44  50  56]
 [ 83  98 113 128]]