- 1.题目
- 2.代码
-
题目要求
-
思路:题目要求用先序和中序遍历来建立二叉树。
-
eg:
For example, given
preorder = [3,9,20,15,7]
inorder = [9,3,15,20,7]
Return the following binary tree:
3
/
9 20
/
15 7
- eg:下面来看一个例子, 某一二叉树的中序和后序遍历分别为:
class Solution
{
public:
TreeNode* buildTree(vector& preorder, vector& inorder)
{
return SubbuildTree(preorder,0,preorder.size()-1,inorder,0,inorder.size()-1);
}
TreeNode* SubbuildTree(vector& preorder, int pleft, int pright,vector& inorder, int ileft, int iright)
{
if ((pleft > pright) || (ileft > iright)) return NULL;
int i=0;
for (i=ileft;ileft=SubbuildTree(preorder,pleft+1,pleft+i-ileft,inorder,ileft,i-1);
root ->right=SubbuildTree(preorder,pleft+i-ileft+1,right,inorder,i+1,iright);
}
};



