- 二叉树是一个比较难搞的问题,但是通过递归实现就代码就比较简单(但是递归需要自己理解,可以通过画图来帮助自己理解)。
- 二叉树的遍历比存储简单,下面的代码也会手动建立一个二叉树,并且创建求他结点个数和二叉树深度的方法,都用到了递归。
- 二叉树里面包括前中后序的遍历,用到递归,方法里面内容相近,主要是输出语句的位置不同。
具体看代码:
package pt;
import java.util.Arrays;
public class BinaryCharTree {
char value;
BinaryCharTree leftChild;
BinaryCharTree rightChild;
public BinaryCharTree(char paraName) {
value = paraName;
leftChild = null;
rightChild = null;
}// of the constructor
public static BinaryCharTree manualConstructorTree() {
// Step 1. Construct a tree with only one node.
BinaryCharTree resultTree = new BinaryCharTree('a');
// Step 2. Construct all nodes. The first node is the root.
// BinaryCharTreeNode tempTreeA=resultTree.root.
BinaryCharTree tempTreeB = new BinaryCharTree('b');
BinaryCharTree tempTreeC = new BinaryCharTree('c');
BinaryCharTree tempTreeD = new BinaryCharTree('d');
BinaryCharTree tempTreeE = new BinaryCharTree('e');
BinaryCharTree tempTreeF = new BinaryCharTree('f');
BinaryCharTree tempTreeG = new BinaryCharTree('g');
// step 3.link all nodes.
resultTree.leftChild = tempTreeB;
resultTree.rightChild = tempTreeC;
tempTreeB.rightChild = tempTreeD;
tempTreeC.leftChild = tempTreeE;
tempTreeD.leftChild = tempTreeF;
tempTreeD.rightChild = tempTreeG;
return resultTree;
}
public void preOrderVisit() {
System.out.println("" + value + " ");
if (leftChild != null) {
leftChild.preOrderVisit();
} // of if
if (rightChild != null) {
rightChild.preOrderVisit();
} // of if
}// of preOrderVisit
public void inOrderVisit() {
if (leftChild != null) {
leftChild.inOrderVisit();
} // of if
System.out.println("" + value + " ");
if (rightChild != null) {
rightChild.postOrderVisit();
} // of if
}// of inOrderVisit
public void postOrderVisit() {
if (leftChild != null) {
leftChild.postOrderVisit();
} // of if
if (rightChild != null) {
rightChild.postOrderVisit();
} // of if
System.out.println("" + value + " ");
}
public int getDepth() {
// It is a leaf.
if ((leftChild == null) && (rightChild == null)) {
return 1;
} // of if
// The depth of the left child.
int tempLeftDepth = 0;
if (leftChild != null) {
tempLeftDepth = leftChild.getDepth();
} // of if
// The depth of the right child.
int tempRightDepth = 0;
if (rightChild != null) {
tempRightDepth = rightChild.getDepth();
} // of if
// The depth should increment by 1.
if (tempLeftDepth >= tempRightDepth) {
return tempLeftDepth + 1;
} else {
return tempRightDepth + 1;
} // of if
}// of getDepth
public int getNumNodes() {
// It is a leaf.
if ((leftChild == null) && (rightChild == null)) {
return 1;
} // of if
// The number of nodes of the left child.
int tempLeftNodes = 0;
if (leftChild != null) {
tempLeftNodes = leftChild.getNumNodes();
} // of if
// The number of nodes of the right child.
int tempRightNodes = 0;
if (rightChild != null) {
tempRightNodes = rightChild.getNumNodes();
} // of if
// The total number of nodes.
return tempLeftNodes + tempRightNodes + 1;
}// of gerNumbders
public static void main(String args[]) {
BinaryCharTree tempTree = manualConstructorTree();
System.out.println("rnPreorder visit:");
tempTree.preOrderVisit();
System.out.println("rnIn-order visit:");
tempTree.inOrderVisit();
System.out.println("rnPost-order visit:");
tempTree.postOrderVisit();
System.out.println("rnrnThe depth is: " + tempTree.getDepth());
System.out.println("The number of nodes is: " + tempTree.getNumNodes());
}// of main
}// of BinaryCharTree



