算法提高之动态规划：背包模型二

• 1、二维费用背包问题（01）
• 2、潜水员（二维费用01）
• 3、数字组合（01 求方案数）
• 4、庆功会(多重背包应用 )
• 5、买书（完全背包求方案数）

#include 

using namespace std;

const int N = 110;

int n, V, M;
int f[N][N];

int main()
{
    cin >> n >> V >> M;

    for (int i = 0; i < n; i ++ )
    {
        int v, m, w;
        cin >> v >> m >> w;
        for (int j = V; j >= v; j -- )
            for (int k = M; k >= m; k -- )
                f[j][k] = max(f[j][k], f[j - v][k - m] + w);
    }

    cout << f[V][M] << endl;

    return 0;
}

#include 
#include 

using namespace std;

const int N = 22, M = 80;

int n, m, K;
int f[N][M];

int main()
{
    cin >> n >> m >> K;

    memset(f, 0x3f, sizeof f);
    f[0][0] = 0;

    while (K -- )
    {
        int v1, v2, w;
        cin >> v1 >> v2 >> w;
        for (int i = n; i >= 0; i -- )
            for (int j = m; j >= 0; j -- )
                f[i][j] = min(f[i][j], f[max(0, i - v1)][max(0, j - v2)] + w);
    }


    cout << f[n][m] << endl;

    return 0;
}

#include 
#include 

using namespace std;

const int N = 10010;

int n, m;
int f[N];

int main()
{
    cin >> n >> m;

    f[0] = 1;
    for (int i = 0; i < n; i ++ )
    {
        int v;
        cin >> v;
        for (int j = m; j >= v; j -- )
        //f[j]不包含i ,f[j-v] 包含i
            f[j] += f[j - v];
    }

    cout << f[m] << endl;

    return 0;
}

#include 

using namespace std;

const int N = 6010;

int n, m;
int f[N];

int main()
{
    cin >> n >> m;

    for (int i = 0; i < n; i ++ )
    {
        int v, w, s;
        cin >> v >> w >> s;
        for (int j = m; j >= 0; j -- )
            for (int k = 0; k <= s && k * v <= j; k ++ )
                f[j] = max(f[j], f[j - k * v] + k * w);
    }

    cout << f[m] << endl;

    return 0;
}

#include 

using namespace std;

const int N = 1010;

int n;
int v[4] = {10, 20, 50, 100};
int f[N];

int main()
{
    cin >> n;

    f[0] = 1;
    for (int i = 0; i < 4; i ++ )
        for (int j = v[i]; j <= n; j ++ )
            f[j] += f[j - v[i]];

    cout << f[n] << endl;

    return 0;
}