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名师互学网 > IT > 软件开发 > 后端开发 > C/C++/C#

XTU OJ 1234 Legal Identifier

C/C++/C# 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

XTU OJ 1234 Legal Identifier

//首先特判掉第一个为数字的 
//然后从第一个(a1)开始判断,锁定串长遍历,如果出现就Break,如果没有则继续。
//strcmp()函数。
#include
#include
char a[34][10]={"auto","break","case","char","const","continue","default","do","double","else","enum",
"extern","float","for","goto","if","int","long","register","return","short","signed","sizeof","static",
"struct","switch","typedef","union","unsigned","void","volatile","while"} ;
char num[34];
int  main()
{
    int k;
    scanf("%d",&k);
    while(k--){
        int flag=1;
        scanf("%s",num);
        int n=strlen(num);
        for(int i=0;i='0'&&num[0]<='9'){
                    flag=0;
                    break;
                   }
                if(num[i]>='0'&&num[i]<='9'||num[i]>='a'&&num[i]<='z'||num[i]>='A'&&num[i]<='Z'||num[i]=='_'){
                    continue;
                   }
                else{
                    flag=0;
                    break;
                }
        }
            if(flag){
                if(n>=2&&n<=8){
                    for(int i=0;i<32;i++){
                        if(strcmp(num,a[i])==0){
                            flag=0;
                            break;
                        }
                        else continue;
                    }
                }
            }
        if(flag==0)    printf("Non");
        else         printf("Yesn");
        }
    return 0;
}

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