- 1.LineToFaceCircle.py
- 2.结果示例
【注1】采用 线动成面的原理，使用一维线去绘制二维平面图形！
【注2】密集的描竖直线即可！
【注3】在一维竖直线上有多点在函数上！即一个x对应多个y值，则先将多个y值求解放在列表y中！ 1.LineToFaceCircle.py
import turtle as tle
import math
tle.speed(0)
tle.delay(0)
tle.pensize(2)
tle.pencolor("blue")
tle.tracer(True)
#tle.tracer(False)
col = ["yellow"]
def subline(x,coll,y=[]):
tle.pencolor(coll)
tle.penup()
tle.goto(x,-220)
tle.pendown()
for i in y:
if x >= -150 and x <-60:
tle.goto(x,i-1.4)
#tle.penup()
tle.pencolor("red")
tle.goto(x,i+1.4)
tle.pencolor(coll)
#tle.pendown()
elif x >= -60 and x <= 0:
tle.goto(x,i-0.8)
#tle.penup()
tle.pencolor("red")
tle.goto(x,i+0.8)
tle.pencolor(coll)
#tle.pendown()
if x > 0 and x <= 60:
tle.goto(x,i-0.8)
#tle.penup()
tle.pencolor("red")
tle.goto(x,i+0.8)
tle.pencolor(coll)
#tle.pendown()
elif x >= 60 and x <= 150:
tle.goto(x,i-1.4)
#tle.penup()
tle.pencolor("red")
tle.goto(x,i+1.4)
tle.pencolor(coll)
#tle.pendown()
tle.goto(x,220)
k = 0
i = -150
while(i<=150):
if k == 1:
k = 0
y = []
if i == 150 or i == -150:
y.append(math.sqrt(22500-i*i))
else:
y.append(-math.sqrt(22500-i*i))
y.append(math.sqrt(22500-i*i))
subline(i,col[k],y)
i = i + 1
k = k + 1
tle.done()
2.结果示例
