您可以使用类似这样 的丑陋技巧,但我认为Tim的答案更好:
SELECt age, nameFROM usersUNIOn ALLSELECt 25 AS age, 'Betty' AS nameWHERe (SELECT COUNT(*) FROM users) > 1

您可以使用类似这样 的丑陋技巧,但我认为Tim的答案更好:
SELECt age, nameFROM usersUNIOn ALLSELECt 25 AS age, 'Betty' AS nameWHERe (SELECT COUNT(*) FROM users) > 1