- 创建一个
date
表并使用JOIN
。 - 计算介于
startdate
和之间的天数enddate
- 划分
totalhours
和totalwages
按天计算。
这是我的解决方案：
SELECt a.empid, b.dd AS date, CAST(a.totalhours AS decimal) / (DATEDIFF(day, startdate, enddate) + 1) AS hours, CAST(a.totalwages AS decimal) / (DATEDIFF(day, startdate, enddate) + 1) AS wagesFROM wages aINNER JOIN dates b ON dd BETWEEN a.startdate AND a.enddate
结果
| EMPID | DATE | HOURS | WAGES |--------------------------------------------------------| ABC123 | 2013-01-01 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-02 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-03 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-04 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-05 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-06 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-07 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-08 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-09 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-10 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-11 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-12 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-13 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-14 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-15 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-16 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-17 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-18 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-19 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-20 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-21 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-22 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-23 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-24 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-25 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-26 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-27 | 5.71428571428 | 64.28571428571 || ABC123 | 2013-01-28 | 5.71428571428 | 64.28571428571 |
sqlfiddle
