对于我来说，进入已经等待了一段时间的python似乎是一项艰巨的任务。我特此介绍我的第一个python脚本：
import sys, rewith open( sys.argv[1] , 'r' ) as f: css = f.read()# remove comments - this will break a lot of hacks :-Pcss = re.sub( r's*', "$$HACK1$$", css ) # preserve IE<6 comment hackcss = re.sub( r'', "", css )css = css.replace( "$$HACK1$$", '' ) # preserve IE<6 comment hack# url() doesn't need quotescss = re.sub( r'url((["'])([^)]*)1)', r'url(2)', css )# spaces may be safely collapsed as generated content will collapse them anywaycss = re.sub( r's+', ' ', css )# shorten collapsable colors: #aabbcc to #abccss = re.sub( r'#([0-9a-f])1([0-9a-f])2([0-9a-f])3(s|;)', r'#1234', css )# fragment values can loose zeroscss = re.sub( r':s*0(.d+([cm]m|e[mx]|in|p[ctx]))s*;', r':1;', css )for rule in re.findall( r'([^{]+){([^}]*)}', css ): # we don't need spaces around operators selectors = [re.sub( r'(?<=[[(>+=])s+|s+(?=[=~^$*|>+])])', r'', selector.strip() ) for selector in rule[0].split( ',' )] # order is important, but we still want to discard repetitions properties = {} porder = [] for prop in re.findall( '(.*?):(.*?)(;|$)', rule[1] ): key = prop[0].strip().lower() if key not in porder: porder.append( key ) properties[ key ] = prop[1].strip() # output rule if it contains any declarations if properties: print "%s{%s}" % ( ','.join( selectors ), ''.join(['%s:%s;' % (key, properties[key]) for key in porder])[:-1] )我相信这可以正常工作，并将其输出在最新的Safari，Opera和Firefox上测试正常。除了下划线和/ **
/骇客，它将破坏CSS骇客！如果您遇到大量黑客攻击（或将它们放在单独的文件中），请不要使用Minifier。
我对python的任何提示表示赞赏。不过请温柔，这是我的第一次。:-)
