提取Google搜索结果

正则表达式对于解析HTML是个坏主意。读取并依赖格式正确的HTML是很神秘的。

尝试使用BeautifulSoup for
Python。这是一个示例脚本，该脚本从site：domain.com Google查询的前10个页面返回URL。

import sys # Used to add the BeautifulSoup folder the import pathimport urllib2 # Used to read the html documentif __name__ == "__main__":    ### import Beautiful Soup    ### Here, I have the BeautifulSoup folder in the level of this Python script    ### So I need to tell Python where to look.    sys.path.append("./BeautifulSoup")    from BeautifulSoup import BeautifulSoup    ### Create opener with Google-friendly user agent    opener = urllib2.build_opener()    opener.addheaders = [('User-agent', 'Mozilla/5.0')]    ### Open page & generate soup    ### the "start" variable will be used to iterate through 10 pages.    for start in range(0,10):        url = "http://www.google.com/search?q=site:stackoverflow.com&start=" + str(start*10)        page = opener.open(url)        soup = BeautifulSoup(page)        ### Parse and find        ### Looks like google contains URLs in <cite> tags.        ### So for each cite tag on each page (10), print its contents (url)        for cite in soup.findAll('cite'): print cite.text

输出：

stackoverflow.com/stackoverflow.com/questionsstackoverflow.com/unansweredstackoverflow.com/usersmeta.stackoverflow.com/blog.stackoverflow.com/chat.meta.stackoverflow.com/...

当然，您可以将每个结果附加到列表中，以便可以将其解析为子域。我几天前刚接触Python并抓取内容，但这应该可以帮助您入门。