>>> from itertools import groupby>>> L = [0, 0, 0, 3, 3, 2, 5, 2, 6, 6]>>> grouped_L = [(k, sum(1 for i in g)) for k,g in groupby(L)]>>> # Or (k, len(list(g))), but that creates an intermediate list>>> grouped_L[(0, 3), (3, 2), (2, 1), (5, 1), (2, 1), (6, 2)]
正如他们所说，电池包括在内。
sumJBernardo的使用和生成器表达建议；见评论。
