按自然顺序对字典关键字进行排序[重复项]

您可以将字典更改为OrderedDict：

import collections, red = {"key1" : 'object', "key11" : 'object', "key2" : 'object', "key22" : 'object', "jay1" : 'object', "jay2" : 'object'}my_fun = lambda k,v: [k, int(v)]d2 = collections.OrderedDict(sorted(d.items(), key=lambda t: my_fun(*re.match(r'([a-zA-Z]+)(d+)',t[0]).groups())))print(d2)#reslt: OrderedDict([('jay1', 'object'), ('jay2', 'object'), ('key1', 'object'), ('key11', 'object'), ('key2', 'object'), ('key22', 'object')])

基本上，这里发生了什么，我将字符串分为“字符串”部分和数字部分。数字部分更改为

int