031 解析工作簿的路径信息

031 解析工作簿的路径信息

from pathlib import Path

file_path = Path(r'D:python_filereceiving.xlsx')
path = file_path.parent         # 提取工作簿所在文件夹的路径
file_name = file_path.name      # 提取工作簿的文件名
stem_name = file_path.stem      # 提取工作簿的文件主名
suf_name = file_path.suffix     # 提取工作簿的扩展名
print(path)
print(file_name)
print(stem_name)
print(suf_name)

C:Usersjjsheanaconda3python.exe “D:/Python/150例/031 解析工作簿的路径信息.py”
D:python_file
receiving.xlsx
receiving
.xlsx

Process finished with exit code 0