代码题 10进制转任意进制

#include
using namespace std;
void convert(int n,int base,char a[]){
	int i=0;
	while(n>0){
		if(base<10||n%base<10){
			a[i++]=n%base+'0';//填空
			}
		else{
			a[i++]=n%base+'A'-10;//填空
		}		
		n=n/base;	
	}
	a[i]='';
} 
void print(char a[]){
	int i=0,j=0,temp=0;
	while(a[j])j++;
	j=j-1;//填空
	for(;i>number>>base;
	convert(number,base,a);//填空
	print(a);
	return 0;
}

运行结果

123 2
结果：1111011
--------------------------------
Process exited after 3.178 seconds with return value 0
请按任意键继续. . .

123 16
结果：7B
--------------------------------
Process exited after 3.909 seconds with return value 0
请按任意键继续. . .