zip与
*和一起使用
map：
>>> map(list, zip(*a))[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'], ['1', '262', '86', '48', '8', '39', '170', '16', '4'], ['1', '56', '84', '362', '33', '82', '296', '40', '3'], ['10', '238', '149', '205', '96', '89', '223', '65', '5'], ['92', '142', '30', '237', '336', '140', '210', '50', '2']]
请注意，它会
map在Python 3中返回一个地图对象，因此您需要
list(map(list, zip(*a)))
使用
list comprehensionwith
zip(*...)，可以像在Python 2和3中一样工作。
[list(x) for x in zip(*a)]
NumPy方式：
>>> import numpy as np>>> np.array(a).T.tolist()[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'], ['1', '262', '86', '48', '8', '39', '170', '16', '4'], ['1', '56', '84', '362', '33', '82', '296', '40', '3'], ['10', '238', '149', '205', '96', '89', '223', '65', '5'], ['92', '142', '30', '237', '336', '140', '210', '50', '2']]
