这是我在评论中所描述的内容，并进行了更改，以正确处理迈克尔·安德森在评论中指出的较大矩形内的圆形情况：
import mathdef collision(rleft, rtop, width, height, # rectangle definition center_x, center_y, radius): # circle definition """ Detect collision between a rectangle and circle. """ # complete boundbox of the rectangle rright, rbottom = rleft + width/2, rtop + height/2 # bounding box of the circle cleft, ctop = center_x-radius, center_y-radius cright, cbottom = center_x+radius, center_y+radius # trivial reject if bounding boxes do not intersect if rright < cleft or rleft > cright or rbottom < ctop or rtop > cbottom: return False # no collision possible # check whether any point of rectangle is inside circle's radius for x in (rleft, rleft+width): for y in (rtop, rtop+height): # compare distance between circle's center point and each point of # the rectangle with the circle's radius if math.hypot(x-center_x, y-center_y) <= radius: return True # collision detected # check if center of circle is inside rectangle if rleft <= center_x <= rright and rtop <= center_y <= rbottom: return True # overlaid return False # no collision detected
