您可以使用
list.count：
board = [2, 4, 0, 2, 8, 4, 4, 8, 0, 2, 0, 0, 4, 0, 2, 2]new_board = [board[i:i+4] for i in range(0, len(board), 4)]final_board = [list(filter(None, i))+([0]*i.count(0)) for i in new_board]last_board = [i for b in final_board for i in b]
输出：
[2, 4, 2, 0, 8, 4, 4, 8, 2, 0, 0, 0, 4, 2, 2, 0]
