下面是如何通过球坐标实现的：
from mpl_toolkits.mplot3d import Axes3Dimport matplotlib.pyplot as pltimport numpy as npfig = plt.figure(figsize=plt.figaspect(1)) # Square figureax = fig.add_subplot(111, projection='3d')coefs = (1, 2, 2) # Coefficients in a0/c x**2 + a1/c y**2 + a2/c z**2 = 1 # Radii corresponding to the coefficients:rx, ry, rz = 1/np.sqrt(coefs)# Set of all spherical angles:u = np.linspace(0, 2 * np.pi, 100)v = np.linspace(0, np.pi, 100)# Cartesian coordinates that correspond to the spherical angles:# (this is the equation of an ellipsoid):x = rx * np.outer(np.cos(u), np.sin(v))y = ry * np.outer(np.sin(u), np.sin(v))z = rz * np.outer(np.ones_like(u), np.cos(v))# Plot:ax.plot_surface(x, y, z, rstride=4, cstride=4, color='b')# Adjustment of the axes, so that they all have the same span:max_radius = max(rx, ry, rz)for axis in 'xyz': getattr(ax, 'set_{}lim'.format(axis))((-max_radius, max_radius))plt.show()上面的程序实际上生成了一个更好看的“正方形”图形。这个解决方案的灵感来自
示例
在Matplotlib的画廊.
