我认为返回相应接头的开始和结束更为自然。例如（0，4）而不是（0，3）
>>> from itertools import groupby>>> def splitWithIndices(s, c=' '):... p = 0... for k, g in groupby(s, lambda x:x==c):... q = p + sum(1 for i in g)... if not k:... yield p, q # or p, q-1 if you are really sure you want that... p = q...>>> a = "This is a sentence">>> list(splitWithIndices(a))[(0, 4), (5, 7), (8, 9), (10, 18)]>>> a[0:4]'This'>>> a[5:7]'is'>>> a[8:9]'a'>>> a[10:18]'sentence'
