这是一种方法：
from more_itertools import consecutive_groupsfinal=pd.concat([df.loc[i].reset_index(drop=True) for i in consecutive_groups(df.index)],axis=1)final.columns=range(len(final.columns))print(final)
0 10 19218.965703 19279.2169561 19247.621650 19330.0873712 19232.651322 19304.316973
