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名师互学网 > IT > 软件开发 > 后端开发 > C/C++/C#

NC97 字符串出现次数的TopK问题(超时未解决)

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NC97 字符串出现次数的TopK问题(超时未解决)


示例1

输入:
["a","b","c","b"],2
返回值:
[["b","2"],["a","1"]]
说明:
"b"出现了2次,记["b","2"],"a"与"c"各出现1次,但是a字典序在c前面,记["a","1"],最后返回[["b","2"],["a","1"]]

示例2

输入:
["123","123","231","32"],2
返回值:
[["123","2"],["231","1"]]
说明:
 "123"出现了2次,记["123","2"],"231"与"32"各出现1次,但是"231"字典序在"32"前面,记["231","1"],最后返回[["123","2"],["231","1"]]   

示例3

输入:
["abcd","abcd","abcd","pwb2","abcd","pwb2","p12"],3
返回值:
[["abcd","4"],["pwb2","2"],["p12","1"]]

code:
class Solution {
public:

    vector > topKstrings(vector& strings, int k) {
        // write code here
        int i;
        mapstringMap;
        map::iterator it;
        for(i=0;isecond+1;
            }
            else
            {
                stringMap.insert(pair(strings[i],1));
            }
        }
		//  sort(stringMap.begin(),stringMap.end(),cmp_by_value);
        vector >res;
        for(it=stringMap.begin();it!=stringMap.end();++it)
        {
            vectortemp;
            temp.push_back(it->first);
            temp.push_back(to_string(it->second));
            res.push_back(temp);
        }
		
        for(int j=0;jres[k+1][0])
                    {
                        isswap=true;
                        swap(res[k][0],res[k+1][0]);
                        swap(res[k][1],res[k+1][1]);
                    }
                }
            }
            if(isswap==false)
                break;
        }
        res.resize(k);
        return res;
        
        
        
    }
};
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