1. 两数之和（C++题解版含VS可运行源程序）

• 1.题解
• • 方法：暴力
• 2.力扣C++源码
• 3.VS可运行源程序

很简单，双层for循环遍历

class Solution {
public:
    vector twoSum(vector& nums, int target) {
        vector res;
		for (int i = 0; i < nums.size(); i++) {
			for (int j = i + 1; j < nums.size(); j++) {
				int sum = nums[i] + nums[j];
				if (sum == target) {
					res.push_back(i);
					res.push_back(j);
					break;
				}
			}
		}
		return res;
    }
};

#include
#include
#include
#include
#include
#include
#include
#include
#include
#pragma warning(disable:4996)
using namespace std;

class Solution {
public:
	vector twoSum(vector& nums, int target) {
		vector res;
		for (int i = 0; i < nums.size(); i++) {
			for (int j = i + 1; j < nums.size(); j++) {
				int sum = nums[i] + nums[j];
				if (sum == target) {
					res.push_back(i);
					res.push_back(j);
					break;
				}
			}
		}
		return res;
	}
};
int main()
{
	printf("输入数组大小：");
	int n;
	scanf("%d", &n);
	printf("输入数组元素：");
	int num;
	vector nums;
	for (int i = 0; i < n; i++) {
		scanf("%d", &num);
		nums.push_back(num);
	}
	printf("输入目标值：");
	int target;
	scanf("%d", &target);
	Solution test;
	vector res = test.twoSum(nums, target);
	printf("符合条件的两个整数的下标分别为：%d %d", res[0], res[1]);

	printf("n");
	system("pause");
	return 0;
}