遍历列表时，请勿修改列表：
for x in schedule: if 'DELETE' in x: schedule.remove(x)
相反，请尝试：
schedule[:] = [x for x in schedule if 'DELETE' not in x]
有关更多信息，请参见如何在迭代时从列表中删除项目？
遍历列表时，请勿修改列表：
for x in schedule: if 'DELETE' in x: schedule.remove(x)
相反，请尝试：
schedule[:] = [x for x in schedule if 'DELETE' not in x]
有关更多信息，请参见如何在迭代时从列表中删除项目？
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