这是我想出的。
基本上，我们有一个循环，可根据所需反应检查每个反应，然后删除旧消息并发送新消息（如果我们看到了所寻找的反应之一）。
from discord.ext import commandsbot = commands.Bot(command_prefix='!')left = '⏪'right = '⏩'messages = ("1", "2", "3")def predicate(message, l, r): def check(reaction, user): if reaction.message.id != message.id or user == bot.user: return False if l and reaction.emoji == left: return True if r and reaction.emoji == right: return True return False return check@bot.command(pass_context=True)async def series(ctx): index = 0 while True: msg = await bot.say(messages[index]) l = index != 0 r = index != len(messages) - 1 if l: await bot.add_reaction(msg, left) if r: await bot.add_reaction(msg, right) # bot.wait_for_reaction react, user = await bot.wait_for_reaction(check=predicate(msg, l, r)) if react.emoji == left: index -= 1 elif react.emoji == right: index += 1 await bot.delete_message(msg)bot.run("TOKEN")有人要求提供一种用于编辑消息的版本，而不是发送新消息，我也将其更新为最新版本：
@bot.command(pass_context=True)async def series(ctx): index = 0 msg = None action = ctx.send while True: res = await action(content=messages[index]) if res is not None: msg = res l = index != 0 r = index != len(messages) - 1 if l: await msg.add_reaction(left) if r: await msg.add_reaction(right) react, user = await bot.wait_for('reaction_add', check=predicate(msg, l, r)) if react.emoji == left: index -= 1 elif react.emoji == right: index += 1 action = msg.edit
