异常处理实现_C++
//
题目描述
根据main 函数和输出结果,写出缺失函数实现。
缺失函数功能为:加薪,若为正常值,则加薪15%。否则若为-1,则抛出异常。
int main()
{
int icnt = 0;
cin >> icnt;
float* pOldArray = new float[icnt];
for(int i = 0; i < icnt; i++)
{
cin >> pOldArray[i];
}
for(int i = 0; i < icnt; i++)
{
try
{
float newSalary = addSalary(pOldArray[i]);
cout << "newSalary = " << newSalary << endl;
}
catch(string s)
{
cout << s << endl;
}
cout << "i = " << i << " finished..." << endl << endl;
}
delete []pOldArray;
return 0;
}
输入
3
1000.5 2000.5 -1
输出
addSalary begin ...
addSalary end...
newSalary = 1150.57
i = 0 finished...
addSalary begin ...
addSalary end...
newSalary = 2300.57
i = 1 finished...
addSalary begin ...
addSalary error : zero salary
zero salary
i = 2 finished...
样例输入 Copy
2
-1 33.33
样例输出 Copy
addSalary begin ...
addSalary error : zero salary
zero salary
i = 0 finished...
addSalary begin ...
addSalary end...
newSalary = 38.3295
i = 1 finished...
//
#include
#include
using namespace std;
float addSalary(float A)
{
cout<<"addSalary begin ..."<