使用itertools和numpy的几种不同方式：
from itertools import groupby, tee, cyclex = [17, 17, 19, 20, 21, 22, 0, 1, 2, 2, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 14, 14, 28, 29, 30, 31, 32, 33, 34, 35, 36, 1, 2, 3, 4,34,54]def sequences(l): x2 = cycle(l) next(x2) grps = groupby(l, key=lambda j: j + 1 == next(x2)) for k, v in grps: if k: yield tuple(v) + (next((next(grps)[1])),)print(list(sequences(x)))[(19, 20, 21, 22), (0, 1, 2), (4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14), (28, 29, 30, 31, 32, 33, 34, 35, 36), (1, 2, 3, 4)]
或者使用python3并从中产生：
def sequences(l): x2 = cycle(l) next(x2) grps = groupby(l, key=lambda j: j + 1 == next(x2)) yield from (tuple(v) + (next((next(grps)[1])),) for k,v in grps if k)print(list(sequences(x)))
在这里使用我的答案的变化与numpy.split：
out = [tuple(arr) for arr in np.split(x, np.where(np.diff(x) != 1)[0] + 1) if arr.size > 1]print(out)[(19, 20, 21, 22), (0, 1, 2), (4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14), (28, 29, 30, 31, 32, 33, 34, 35, 36), (1, 2, 3, 4)]
类似于ekhumoro的回答：
def sequences(x): it = iter(x) prev, temp = next(it), [] while prev is not None: start = next(it, None) if prev + 1 == start: temp.append(prev) elif temp: yield tuple(temp + [prev]) temp = [] prev = start
获取长度和元组：
def sequences(l): x2 = cycle(l) next(x2) grps = groupby(l, key=lambda j: j + 1 == next(x2)) for k, v in grps: if k: t = tuple(v) + (next(next(grps)[1]),) yield t, len(t)def sequences(l): x2 = cycle(l) next(x2) grps = groupby(l, lambda j: j + 1 == next(x2)) yield from ((t, len(t)) for t in (tuple(v) + (next(next(grps)[1]),) for k, v in grps if k))def sequences(x): it = iter(x) prev, temp = next(it), [] while prev is not None: start = next(it, None) if prev + 1 == start: temp.append(prev) elif temp: yield tuple(temp + [prev]), len(temp) + 1 temp = [] prev = start
这三个输出都将相同：
[((19, 20, 21, 22), 4), ((0, 1, 2), 3), ((4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14), 11), ((28, 29, 30, 31, 32, 33, 34, 35, 36), 9), ((1, 2, 3, 4), 4)]
