21.12.09

P5728 【深基5.例5】旗鼓相当的对手 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)https://www.luogu.com.cn/problem/P5728

#include
#include
using namespace std;

int main() {
	int ans[1010][3]{}, n, sum1 = 0, sum2 = 0, f = 0;
	cin >> n;

	for (int i = 0; i < n; i++) {
		for (int k = 0; k < 3; k++) {
			cin >> ans[i][k];
		}
	}

	
	for (int i = 0; i < n; i++) {
		for (int g = i + 1; g < n; g++) {
			sum1 = 0;   sum2 = 0;
			for (int k = 0; k < 3; k++) {
				
				if (fabs(ans[i][k] - ans[g][k]) <= 5) {
					sum1 += ans[i][k];
					sum2 += ans[g][k];
				}
				else 
					break;			
				if (k == 2 && fabs(sum1 - sum2) <= 10)
					f++;
			}
		}
	}
	
	cout << f;
	return 0;
}

olol 

for (int i = 0; i < n; i++) {
        for (int g = i + 1; g < n; g++) {

一个元素和后面的每一个元素进行对比

修改：