如何将Python日期时间日期转换为十进制/浮点数

from datetime import datetime as dtimport timedef toYearFraction(date):    def sinceEpoch(date): # returns seconds since epoch        return time.mktime(date.timetuple())    s = sinceEpoch    year = date.year    startOfThisYear = dt(year=year, month=1, day=1)    startOfNextYear = dt(year=year+1, month=1, day=1)    yearElapsed = s(date) - s(startOfThisYear)    yearDuration = s(startOfNextYear) - s(startOfThisYear)    fraction = yearElapsed/yearDuration    return date.year + fraction

演示：

>>> toYearFraction(dt.today())2011.47447514

此方法可能精确到秒（如果是夏令时或其他奇怪的区域性影响生效，则为小时）。在leap年期间也可以正常工作。如果您需要极高的分辨率（例如由于地球自转的变化），那么最好查询网络服务。