本文主要针对c++中常用replace函数用法给出九个样例程序:
用法一:
int main()
{
string line = "this@ is@ a test string!";
line = line.replace(line.find("@"), 1, ""); //从第一个@位置替换第一个@为空
cout << line << endl;
return 0;
}
运行结果:
用法二:
int main()
{
string line = "this@ is@ a test string!";
line = line.replace(line.begin(), line.begin()+6, ""); //用str替换从begin位置开始的6个字符
cout << line << endl;
return 0;
}
运行结果:
用法三:
int main()
{
string line = "this@ is@ a test string!";
string substr = "12345";
line = line.replace(0, 5, substr, substr.find("1"), 3); //用substr的指定子串(从1位置数共3个字符)替换从0到5位置上的line
cout << line << endl;
return 0;
}
运行结果:
用法四:string转char*时编译器可能会报出警告,不建议这样做
int main()
{
string line = "this@ is@ a test string!";
char* str = "12345";
line = line.replace(0, 5, str); //用str替换从指定位置0开始长度为5的字符串
cout << line << endl;
return 0;
}
运行结果:
用法五:string转char*时编译器可能会报出警告,不建议这样做
int main()
{
string line = "this@ is@ a test string!";
char* str = "12345";
line = line.replace(line.begin(), line.begin()+9, str); //用str替换从指定迭代器位置的字符串
cout << line << endl;
return 0;
}
运行结果:
用法六:string转char*时编译器可能会报出警告,不建议这样做
int main()
{
string line = "this@ is@ a test string!";
char* str = "12345";
line = line.replace(0, 9, str, 4); //用str的前4个字符替换从0位置开始长度为9的字符串
cout << line << endl;
return 0;
}
运行结果:
用法七:string转char*时编译器可能会报出警告,不建议这样做
int main()
{
string line = "this@ is@ a test string!";
char* str = "12345";
line = line.replace(line.begin(), line.begin()+9, str, 4); //用str的前4个字符替换指定迭代器位置的字符串
cout << line << endl;
return 0;
}
运行结果:
用法八:
int main()
{
string line = "this@ is@ a test string!";
char c = '1';
line = line.replace(0, 9, 3, c); //用重复3次的c字符替换从指定位置0长度为9的内容
cout << line << endl;
return 0;
}
运行结果:
用法九:
int main()
{
string line = "this@ is@ a test string!";
char c = '1';
line = line.replace(line.begin(), line.begin()+9, 3, c); //用重复3次的c字符替换从指定迭代器位置的内容
cout << line << endl;
return 0;
}
运行结果:
注:所有使用迭代器类型的参数不限于string类型,可以为vector、list等其他类型迭代器。



