如此答案所示，pyparsing似乎是正确的工具：
inputdata = '(1 ((st 8) (pitch 67) (dur 4) (keysig 1) (timesig 12) (fermata 0))((st 12) (pitch 67) (dur 8) (keysig 1) (timesig 12) (fermata 0)))'from pyparsing import OneOrMore, nestedExprdata = oneOrMore(nestedExpr()).parseString(inputdata)print data# [['1', [['st', '8'], ['pitch', '67'], ['dur', '4'], ['keysig', '1'], ['timesig', '12'], ['fermata', '0']], [['st', '12'], ['pitch', '67'], ['dur', '8'], ['keysig', '1'], ['timesig', '12'], ['fermata', '0']]]]
为了完整起见，这是格式化结果的格式（使用texttable）：
from texttable import Texttabletab = Texttable()for row in data.asList()[0][1:]: row = dict(row) tab.header(row.keys()) tab.add_row(row.values())print tab.draw()+ --------- + -------- + ---- + ------- + ----- + --------- +| Timesig | keyig | st | 音高| dur | Fermata |+ ========= + ======== + ============================= +| 12 | 1 | 8 | 67 | 4 | 0 |+ --------- + -------- + ---- + ------- + ----- + --------- +| 12 | 1 | 12 | 67 | 8 | 0 |+ --------- + -------- + ---- + ------- + ----- + --------- +
将该数据转换回Lisp表示法：
def lisp(x): return '(%s)' % ' '.join(lisp(y) for y in x) if isinstance(x, list) else xd = lisp(d[0])
