根据熊猫中的列进行分组和自动递增

In [10]: df['counter'] = df.groupby(['Product','SubProd']).cumcount()+1In [11]: dfOut[11]: Product SubProd  counter4/20/2012        A      BL        14/27/2012        A      BL        25/4/2012         A      BL        35/11/2012        A      BL        45/18/2012        A      BL        54/20/2012        A      lk        14/27/2012        A      lk        25/4/2012         A      lk        35/11/2012        A      lk        45/18/2012        A      lk        55/25/2012        A      lk        610/31/2014       B      po        111/7/2014        B      po        211/14/2014       B      po        311/21/2014       B      po        411/28/2014       B      po        5