我只使用一个异常处理程序，它将捕获
KeyboardInterrupt并存储异常。然后，在迭代完成的那一刻，如果有一个异常待处理，我将中断循环并重新引发该异常（以使正常的异常处理有机会发生）。
这有效（已在Python 2.7上测试）：
x = 1print "script started."stored_exception=Nonewhile True: try: print "Processing file #",x,"started...", # do something time-cosnuming time.sleep(1) print " finished." if stored_exception: break x += 1 except KeyboardInterrupt: stored_exception=sys.exc_info()print "Bye"print "x=",xif stored_exception: raise stored_exception[0], stored_exception[1], stored_exception[2]sys.exit()
编辑： 由于已在评论中发现，此答案对于原始海报不令人满意，这是基于线程的解决方案：
import timeimport sysimport threadingprint "script started."class MyProcessingThread(threading.Thread): def __init__(self): threading.Thread.__init__(self) def run(self): print "Processing file #",x,"started...", # do something time-cosnuming time.sleep(1) print " finished."for x in range(1,4): task = MyProcessingThread() task.start() try: task.join() except KeyboardInterrupt: breakprint "Bye"print "x=",xsys.exit()
