我找到了一个可以帮助我们将FastAPI表单也用作pydantic的解决方案：）
我的代码：
class AnyForm(baseModel): any_param: str any_other_param: int = 1 @classmethod def as_form( cls, any_param: str = Form(...), any_other_param: int = Form(1) ) -> AnyForm: return cls(any_param=any_param, any_other_param=any_other_param)@router.post('')async def any_view(form_data: AnyForm = Depends(AnyForm.as_form)): ...它以
我通常认为的形式大张旗鼓地显示，可以写得更通用，也许我会返回并编辑答案。
[更新]
我已经把它写成装饰器了
import inspectfrom typing import Typefrom fastapi import Formfrom pydantic import baseModelfrom pydantic.fields import ModelFielddef as_form(cls: Type[baseModel]): new_parameters = [] for field_name, model_field in cls.__fields__.items(): model_field: ModelField # type: ignore if not model_field.required: new_parameters.append( inspect.Parameter( model_field.alias, inspect.Parameter.POSITIONAL_ONLY, default=Form(model_field.default), annotation=model_field.outer_type_, ) ) else: new_parameters.append( inspect.Parameter( model_field.alias, inspect.Parameter.POSITIONAL_ONLY, default=Form(...), annotation=model_field.outer_type_, ) ) async def as_form_func(**data): return cls(**data) sig = inspect.signature(as_form_func) sig = sig.replace(parameters=new_parameters) as_form_func.__signature__ = sig # type: ignore setattr(cls, 'as_form', as_form_func) return cls
用法看起来像
class Test1(baseModel): a: str b: int@as_formclass Test(baseModel): param: str test: List[Test1] test1: Test1 b: int = 1 a: str = '2342'@router.post('/me', response_model=Test)async def me(request: Request, form: Test = Depends(Test.as_form)): return form
