您可以使用以下配方：
from operator import itemgetterfrom itertools import groupbyfull_list = [0,1,2,3,10,11,12,59]cont = [map(itemgetter(1), g) for k, g in groupby(enumerate(full_list), lambda (i,x):i-x)]# [[0, 1, 2, 3], [10, 11, 12], [59]]
您可以使用以下配方：
from operator import itemgetterfrom itertools import groupbyfull_list = [0,1,2,3,10,11,12,59]cont = [map(itemgetter(1), g) for k, g in groupby(enumerate(full_list), lambda (i,x):i-x)]# [[0, 1, 2, 3], [10, 11, 12], [59]]
名师互学网 版权所有 (c)2021-2022 ICP备案号：晋ICP备2021003244-6号
